BMS分析2【葛立恒数二吧】

xyl
TREE
10

之前那个贴沉了，那再发一个
(0)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(1,1,1)=ψ(Ω_(ω+1)+Ω_ω)
(0)(1,1,1)(2,1)(3,2)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω+1)*2)
(0)(1,1,1)(2,1)(3,2)(2)=ψ(Ω_(ω+1)*ω)
(0)(1,1,1)(2,1)(3,2)(2,1)=ψ(Ω_(ω+1)*Ω)
(0)(1,1,1)(2,1)(3,2)(2,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω)（没问题吧）
(0)(1,1,1)(2,1)(3,2)(2,1)(1,1,1)(2,1)(3,2)(2,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω*2)
(0)(1,1,1)(2,1)(3,2)(2,1)(2)=ψ(Ω_(ω+1)*Ω_ω*ω)
(0)(1,1,1)(2,1)(3,2)(2,1)(2,1)=ψ(Ω_(ω+1)*Ω_ω*Ω)
(0)(1,1,1)(2,1)(3,2)(2,1)(2,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^2)
(0)(1,1,1)(2,1)(3,2)(2,1)(3)=ψ(Ω_(ω+1)*Ω_ω^ω)
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)=ψ(Ω_(ω+1)*Ω_ω^Ω)
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^Ω_ω)（没问题吧）
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)(2,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^(Ω_ω+1))
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)(2,1)(3,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^(Ω_ω*2))
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)(3,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^Ω_ω^2)
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)(4,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^Ω_ω^Ω_ω)
(0)(1,1,1)(2,1)(3,2)(2,1)(3,2)

送TA礼物

IP属地:天津

来自Android客户端1楼2024-03-09 14:26回复

xyl
TREE
10

好吧从第三步就错了。。。(0)(1,1,1)(2,1)(3,2)(1,1,1)(2,1)(3,2)是ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1))。。。
主要是受了(0)(1,1,1)(1,1,1)是ψ(Ω_ω*2)的误导

IP属地:天津

来自Android客户端3楼2024-03-09 14:29

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(1,1,1)=ψ(Ω_(ω+1)+Ω_ω)
(0)(1,1,1)(2,1)(3,2)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(2)=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+1))
(0)(1,1,1)(2,1)(3,2)(2,1)=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+Ω))
(0)(1,1,1)(2,1)(3,2)(2,1)(1,1,1)=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+Ω_ω)（没问题吧）
(0)(1,1,1)(2,1)(3,2)(2,1)(2,1)(1,1,1)
=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+Ω_ω*2)
(0)(1,1,1)(2,1)(3,2)(2,1)(3,1)
=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+Ω_ω*Ω))
(0)(1,1,1)(2,1)(3,2)(2,1)(3,2)=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+ψ_ω(Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(3)=ψ(Ω_(ω+1)*2)

IP属地:天津

来自Android客户端4楼2024-03-09 14:41

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xyl
TREE
10

(0)(1,1,1)(2,1)(3,2)(3)
=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+1)))
(0)(1,1,1)(2,1)(3,2)(3,1)
=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+Ω)))
(0)(1,1,1)(2,1)(3,2)(3,1)(4,2)
=ψ(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+ψ_ω(Ω_(ω+1)+ψ_ω(Ω_(ω+1))))
(0)(1,1,1)(2,1)(3,2)(3,2)=ψ(Ω_(ω+1)*2)
这回对了吧

IP属地:天津

来自Android客户端5楼2024-03-09 18:02

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2)(3,2)(3,2)=ψ(Ω_(ω+1)*3)
(0)(1,1,1)(2,1)(3,2)(4)=ψ(Ω_(ω+1)*ω)
(0)(1,1,1)(2,1)(3,2)(4,1)=ψ(Ω_(ω+1)*Ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)
=ψ(Ω_(ω+1)*Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω*2)（没问题吧，别又错了）
(0)(1,1,1)(2,1)(3,2)(4,1)(2,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^2)
(0)(1,1,1)(2,1)(3,2)(4,1)(2,1)(3,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(2,1)(3,2)=ψ(Ω_(ω+1)*ψ_ω(Ω_(ω+1))

IP属地:天津

来自Android客户端6楼2024-03-09 18:21

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折合成φ

IP属地:河北

7楼2024-03-09 18:35

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω+Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)(2,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω+Ω_ω^2)
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)(2,1)(3,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω+Ω_ω^Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω+1)*Ω_ω+ψ_ω(Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)(2,1)(3,2)(4,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω+ψ_ω(Ω_(ω+1)*Ω_ω))

IP属地:天津

来自Android客户端8楼2024-03-09 18:36

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2)(4,1)(2)=ψ(Ω_(ω+1)*Ω_ω+ψ_ω(Ω_(ω+1)+1))
(0)(1,1,1)(2,1)(3,2)(4,1)(3,2)=ψ(Ω_(ω+1)*Ω_ω+Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,1)(3,2)(4,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω*2)
(0)(1,1,1)(2,1)(3,2)(4,1)(4)=ψ(Ω_(ω+1)*Ω_ω*ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(4,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^2)
(0)(1,1,1)(2,1)(3,2)(4,1)(5,1)(1,1,1)=ψ(Ω_(ω+1)*Ω_ω^Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,1)(5,2)=ψ(Ω_(ω+1)*ψ_ω(Ω_(ω+1)))
(0)(1,1,1)(2,1)(3,2)(4,1)(5,2)(6,1)(7,2)
=ψ(Ω_(ω+1)*ψ_ω(Ω_(ω+1)*ψ_ω(Ω_(ω+1)
(0)(1,1,1)(2,1)(3,2)(4,2)=ψ(Ω_(ω+1)^2)
(0)(1,1,1)(2,1)(3,2)(4,2)(3,2)=ψ(Ω_(ω+1)^2+Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,2)(3,2)(4,2)=ψ(Ω_(ω+1)^2*2)
(0)(1,1,1)(2,1)(3,2)(4,2)(4)=ψ(Ω_(ω+1)^2*ω)
(0)(1,1,1)(2,1)(3,2)(4,2)(4,2)=ψ(Ω_(ω+1)^3)
(0)(1,1,1)(2,1)(3,2)(4,2)(5,2)=ψ(Ω_(ω+1)^Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,2)(5,2)(6,2)=ψ(Ω_(ω+1)^Ω_(ω+1)^Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,3)=ψ(Ω_(ω+2))

IP属地:天津

来自Android客户端9楼2024-03-09 21:25

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2)(4,3)=ψ(Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2)(4,3)(1,1,1)(2,1)(3,2)(4,3)=ψ(Ω_(ω+2)+ψ_ω(Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2)(4,3)(3,2)=ψ(Ω_(ω+2)+Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,3)(3,2)(4,2)=ψ(Ω_(ω+2)+Ω_(ω+1)^2)
(0)(1,1,1)(2,1)(3,2)(4,3)(3,2)(4,3)=ψ(Ω_(ω+2)+ψ_(ω+1)(Ω_(ω+2)))
(0)(1,1,1)(2,1)(3,2)(4,3)(4)=ψ(Ω_(ω+2)+ψ_(ω+1)(Ω_(ω+2)+1))
(0)(1,1,1)(2,1)(3,2)(4,3)(4,3)=ψ(Ω_(ω+2)*2)
(0)(1,1,1)(2,1)(3,2)(4,3)(5,1)(1,1,1)=ψ(Ω_(ω+2)*Ω_ω)
(0)(1,1,1)(2,1)(3,2)(4,3)(5,2)=ψ(Ω_(ω+2)*Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2)(4,3)(5,3)=ψ(Ω_(ω+2)^2)
(0)(1,1,1)(2,1)(3,2)(4,3)(5,3)(6,3)=ψ(Ω_(ω+2)^Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2)(4,3)(5,4)=ψ(Ω_(ω+3))
(0)(1,1,1)(2,1)(3,2)(4,3)(5,4)(6,5)=ψ(Ω_(ω+4))
(0)(1,1,1)(2,1)(3,2,1)=ψ(Ω_(ω2))

IP属地:天津

来自Android客户端10楼2024-03-10 11:45

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2,1)(1,1,1)=ψ(Ω_(ω2)+Ω_ω)
(0)(1,1,1)(2,1)(3,2,1)(3,2)=ψ(Ω_(ω2)+Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2,1)(3,2)(4,3)=ψ(Ω_(ω2)+ψ_(ω+1)(Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2,1)(3,2)(4,3,1)(4,3)=ψ(Ω_(ω2)+Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2,1)(3,2,1)=ψ(Ω_(ω2)*2)
(0)(1,1,1)(2,1)(3,2,1)(3,2,1)(3,2,1)=ψ(Ω_(ω2)*3)
(0)(1,1,1)(2,1)(3,2,1)(4)=ψ(Ω_(ω2)*ω)
(0)(1,1,1)(2,1)(3,2,1)(4,1)=ψ(Ω_(ω2)*Ω)
(0)(1,1,1)(2,1)(3,2,1)(4,1)(1,1,1)=ψ(Ω_(ω2)*Ω_ω)
(0)(1,1,1)(2,1)(3,2,1)(4,1)(3,2)=ψ(Ω_(ω2)*Ω_(ω+1))

IP属地:天津

来自Android客户端11楼2024-03-10 16:13

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xyl
TREE
10

(0)(1,1,1)(2,1)(3,2,1)(4,1)(2)=ψ(Ω_(ω2)*Ω_ω+ψ_ω(Ω_(ω2)*Ω_ω+1)
(0)(1,1,1)(2,1)(3,2,1)(4,1)(3,2)=ψ(Ω_(ω2)*Ω_ω+Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2,1)(4,1)(3,2,1)(4,1)=ψ(Ω_(ω2)*Ω_ω*2)
(0)(1,1,1)(2,1)(3,2,1)(4,1)(4,1)(1,1,1)=ψ(Ω_(ω2)*Ω_ω^2)
(0)(1,1,1)(2,1)(3,2,1)(4,1)(5,2)=ψ(Ω_(ω2)*ψ_ω(Ω_(ω+1)))
(0)(1,1,1)(2,1)(3,2,1)(4,1)(5,2,1)=ψ(Ω_(ω2)*ψ_ω(Ω_(ω2)))
(0)(1,1,1)(2,1)(3,2,1)(4,1)(5,2,1)(6,1)(7,2,1)=ψ(Ω_(ω2)*ψ_ω(Ω_(ω2)*ψ_ω(Ω_(ω2))))
(0)(1,1,1)(2,1)(3,2,1)(4,2)=ψ(Ω_(ω2)*Ω_(ω+1)

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来自Android客户端12楼2024-03-10 16:29

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2)=ψ(Ω_(ω2)*Ω_(ω+1)+Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2)(4,3,1)(5,2)=ψ(Ω_(ω2)*Ω_(ω+1)+ψ_(ω+1)ψ(Ω_(ω2)*Ω_(ω+1))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2)(4,3,1)(5,2)(4,3)=ψ(Ω_(ω2)*Ω_(ω+1)+Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2)(4,3,1)(5,2)(4,3,1)(5,2)=ψ(Ω_(ω2)*Ω_(ω+1)*2)
(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2)(4,3,1)(5,2)(6,3,1)=ψ(Ω_(ω2)*ψ_(ω+1)(Ω_(ω2)))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2)(4,3,1)(5,3)=ψ(Ω_(ω2)*Ω_(ω+2))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(3,2,1)=ψ(Ω_(ω2)^2)

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来自Android客户端13楼2024-03-10 16:50

xyl
TREE
10

(0)(1,1,1)(2,1)(3,2,1)(4,2)(4,2)(3,2,1)=ψ(Ω_(ω2)^3)
(0)(1,1,1)(2,1)(3,2,1)(4,2)(5,2)(3,2,1)=ψ(Ω_(ω2)^Ω_(ω2))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(5,3)=ψ(Ω_(ω2+1))
(0)(1,1,1)(2,1)(3,2,1)(4,2)(5,3,1)=ψ(Ω_(ω3))
(0)(1,1,1)(2,1,1)=ψ(Ω_(ω^2))

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来自Android客户端14楼2024-03-10 16:53

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你是前年带我入门大数那位？

IP属地:江苏

来自Android客户端15楼2024-03-11 21:03

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xyl
TREE
10

(0)(1,1,1)(2,1,1)(1,1,1)=ψ(Ω_(ω^2)+Ω_ω)（没问题吧，害怕BMS忽然来个大提升）
(0)(1,1,1)(2,1,1)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω^2)+ψ_ω(Ω_(ω+1))
(0)(1,1,1)(2,1,1)(1,1,1)(2,1)(3,2,1)(4,2,1)=ψ(Ω_(ω^2)+ψ_ω(Ω_(ω^2))
(0)(1,1,1)(2,1,1)(1,1,1)(2,1)(3,2,1)(4,2,1)(3,2)=ψ(Ω_(ω^2)+Ω_(ω+1))
(0)(1,1,1)(2,1,1)(1,1,1)(2,1)(3,2,1)(4,2,1)(3,2)(4,3,1)(5,3,1)(4,3)=ψ(Ω_(ω^2)+Ω_(ω+2))
(0)(1,1,1)(2,1,1)(1,1,1)(2,1)(3,2,1)(4,2,1)(3,2,1)=ψ(Ω_(ω^2)+Ω_(ω2))
(0)(1,1,1)(2,1,1)(1,1,1)(2,1,1)=ψ(Ω_(ω^2)*2)
(0)(1,1,1)(2,1,1)(2)=ψ(Ω_(ω^2)*ω)
(0)(1,1,1)(2,1,1)(2,1)=ψ(Ω_(ω^2)*Ω)
(0)(1,1,1)(2,1,1)(2,1)(1,1,1)=ψ(Ω_(ω^2)*Ω_ω)
(0)(1,1,1)(2,1,1)(2,1)(1,1,1)(2,1,1)=ψ(Ω_(ω^2)^2)（?）
(0)(1,1,1)(2,1,1)(2,1)(2,1)(1,1,1)(2,1,1)=ψ(Ω_(ω^2)^3)（?）
(0)(1,1,1)(2,1,1)(2,1)(3,1)(1,1,1)(2,1,1)=ψ(Ω_(ω^2)^Ω_(ω^2))（?）
(0)(1,1,1)(2,1,1)(2,1)(3,2)=ψ(Ω_(ω^2+1))

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来自Android客户端16楼2024-03-15 09:25

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