葛立恒数二吧 关注:763贴子:65,348
  • 41回复贴,共1


IP属地:天津来自Android客户端1楼2024-03-23 00:09回复
    @紫然茗 对吗


    IP属地:天津来自Android客户端2楼2024-03-23 00:09
    回复
      1,4,4你要怎么办


      IP属地:湖南来自Android客户端3楼2024-03-23 00:28
      收起回复
        展开1,4,6,3,7,9,7


        IP属地:天津来自Android客户端4楼2024-03-23 09:46
        收起回复
          @jdihdib
          1,4,6,3,7,9,7=
          a_(3n-2)=n(n+1)/2
          a_(3n-1)=(n+1)(n+2)/2+1
          a_(3n)=(n+1)(n+2)/2+3


          IP属地:天津来自Android客户端7楼2024-03-23 12:49
          收起回复
            现在开始分析吧,我已经不知道我在搞大数学还是数学了
            1=1
            1,2=ω
            1,2,1,2=ω2
            1,2,2=ω^2
            1,2,3=ω^ω
            1,2,3,4=ω^ω^ω
            1,3=ε0
            1,3,2=ε0*ω
            1,3,2,4=ε0^2
            1,3,2,4,2,4=ε0^3
            1,3,2,4,3=ε0^ω
            1,3,2,4,3,5=ε0^ε0
            1,3,3=ε1
            1,3,3,3=ε2
            1,3,4=εω
            1,3,4,6=εε0
            1,3,5=ζ0


            IP属地:天津来自Android客户端8楼2024-03-23 13:11
            回复
              1,3,5,3=ε(ζ0+1)
              1 3 5 3 3=ε(ζ0+2)
              1 3 5 3 4 6 8=ε(ζ0*2)
              1 3 5 3 4 6 8 6=εε(ζ0+1)
              1 3 5 3 5=ζ1
              1 3 5 4=ζω
              1 3 5 4 6 8=ζζ0
              1 3 5 5=η0
              1 3 5 5 5=φ(4,0)
              1 3 5 6=φ(ω,0)
              1 3 5 6 8 10 11=φ(φ(ω,0),0)
              1 3 5 7=Γ0
              1 3 5 7 3=ε(Γ0+1)
              1 3 5 7 3 5 6=φ(ω,Γ0+1)
              1 3 5 7 3 5 6 8 10 12=φ(Γ0,1)
              1 3 5 7 3 5 7=Γ1
              1 3 5 7 4=Γω
              1 3 5 7 4 6 8 10=ΓΓ0
              1 3 5 7 5=φ(1,1,0)
              1 3 5 7 5 5=φ(1,2,0)
              1 3 5 7 5 6=φ(1,ω,0)
              1 3 5 7 5 7=φ(2,0,0)
              1 3 5 7 6=φ(ω,0,0)
              1 3 5 7 7=φ(1,0,0,0)
              1 3 5 7 7 7=φ(1,0,0,0,0)
              1 3 5 7 8=φ(1@ω)
              1 3 5 7 8 10 12 14 15=φ(1@φ(1@ω))
              1 3 5 7 9=ψ(Ω^Ω^Ω)


              IP属地:天津来自Android客户端9楼2024-03-23 13:37
              回复
                1,4,9,11,9=
                a_(4n-3)=3n^2-2n
                a_(4n-2)=3n^2+n
                a_(4n-1)=3n^2+4n+2
                a_(4n)=3n^2+7n+1


                IP属地:天津来自Android客户端10楼2024-03-23 14:08
                收起回复
                  另外,没什么必要分析0-Y,这东西和BMS是逐项互译的


                  IP属地:天津来自Android客户端11楼2024-03-23 14:21
                  收起回复
                    1 3 5 7 9 11=(0)(1,1)(2,1)(3,1)(4,1)(5,1)
                    1 3 6=(0)(1,1)(2,2)=ψ(Ω_2)
                    1 3 6 3=(0)(1,1)(2,2)(1,1)=ψ(Ω_2+Ω)
                    1 3 6 3 6=(0)(1,1)(2,2)(1,1)(2,2)=ψ(Ω_2+ψ_1(Ω_2))
                    1 3 6 4=(0)(1,1)(2,2)(2)=ψ(Ω_2+ψ_1(Ω_2+1))
                    1 3 6 5=(0)(1,1)(2,2)(2,1)=ψ(Ω_2+ψ_1(Ω_2+Ω))
                    1 3 6 6=(0)(1,1)(2,2)(2,2)=ψ(Ω_2*2)
                    1 3 6 7=(0)(1,1)(2,2)(3)=ψ(Ω_2*ω)
                    1 3 6 8=(0)(1,1)(2,2)(3,1)=ψ(Ω_2*Ω)
                    1 3 6 8 8=(0)(1,1)(2,2)(3,1)(3,1)=ψ(Ω_2*Ω^2)
                    1 3 6 8 10=(0)(1,1)(2,2)(3,1)(4,1)=ψ(Ω_2*Ω^Ω)
                    1 3 6 8 11=(0)(1,1)(2,2)(3,1)(4,2)=ψ(Ω_2*ψ_1(Ω_2))
                    1 3 6 9=(0)(1,1)(2,2)(3,2)=ψ(Ω_2^2)
                    1 3 6 9 9=(0)(1,1)(2,2)(3,2)(3,2)=ψ(Ω_2^3)
                    1 3 6 9 11=(0)(1,1)(2,2)(3,2)(4,1)=ψ(Ω_2^Ω)
                    1 3 6 9 12=(0)(1,1)(2,2)(3,2)(4,2)=ψ(Ω_2^Ω_2)
                    1 3 6 10=(0)(1,1)(2,2)(3,3)=ψ(Ω_3)


                    IP属地:天津来自Android客户端12楼2024-03-23 14:51
                    收起回复
                      1 3 6 10 15=(0)(1,1)(2,2)(3,3)(4,4)=ψ(Ω_4)
                      1 4=(0)(1,1,1)=ψ(Ω_ω)
                      1 4 3=(0)(1,1,1)(1,1)=ψ(Ω_ω+Ω)
                      1 4 3 7=(0)(1,1,1)(1,1)(2,2,1)=ψ(Ω_ω+ψ_1(Ω_ω))
                      1 4 3 7 6=(0)(1,1,1)(1,1)(2,2,1)(2,2)=ψ(Ω_ω+Ω_2)
                      1 4 4=(0)(1,1,1)(1,1,1)=ψ(Ω_ω*2)
                      1 4 5=(0)(1,1,1)(2)=ψ(Ω_ω*ω)
                      1 4 6=(0)(1,1,1)(2,1)=ψ(Ω_ω*Ω)
                      1 4 6 3=(0)(1,1,1)(2,1)(1,1)=ψ(Ω_ω*Ω+Ω)
                      1 4 6 3 7=(0)(1,1,1)(2,1)(1,1)(2,2,1)=ψ(Ω_ω*Ω+ψ_1(Ω_ω))
                      1 4 6 3 7 9 6=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(2,2)=ψ(Ω_ω*Ω+Ω_2)
                      1 4 6 3 7 9 6 11 13 10=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(2,2)(3,3,1)(4,1)(3,3)=ψ(Ω_ω*Ω+Ω_3)
                      1 4 6 3 7 9 7=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(2,2,1)=ψ(Ω_ω*Ω+Ω_ω)(你们为啥都用这个表达式举例啊,它长得好看吗)
                      1 4 6 3 7 9 7 9=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(2,2,1)(3,1)=ψ(Ω_ω*Ω2)
                      1 4 6 3 7 9 9=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(3,1)=ψ(Ω_ω*Ω^2)
                      1 4 6 3 7 9 11=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(4,1)=ψ(Ω_ω*Ω^2)
                      1 4 6 3 7 9 12=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(4,2)=ψ(Ω_ω*ψ_1(Ω_2))
                      1 4 6 3 7 9 13=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,1)(4,2,1)=ψ(Ω_ω*ψ_1(Ω_ω))
                      1 4 6 3 7 10=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,2)=ψ(Ω_ω*Ω_2)
                      1 4 6 3 7 10 6 11 15=(0)(1,1,1)(2,1)(1,1)(2,2,1)(3,2)(2,2)(3,3,1)(4,3)=ψ(Ω_ω*Ω_3)
                      1 4 6 4=(0)(1,1,1)(2,1)(1,1,1)=ψ(Ω_ω^2)


                      IP属地:天津来自Android客户端13楼2024-03-23 16:38
                      收起回复
                        1 4 6 5=(0)(1,1,1)(2,1)(2)=ψ(Ω_ω^2*ω)
                        1 4 6 6=(0)(1,1,1)(2,1)(2,1)=ψ(Ω_ω^2*Ω)
                        1 4 6 8=(0)(1,1,1)(2,1)(3,1)=ψ(Ω_ω^Ω)
                        1 4 6 8 10=(0)(1,1,1)(2,1)(3,1)(4,1)=ψ(Ω_ω^Ω_ω^Ω)
                        1 4 6 9=(0)(1,1,1)(2,1)(3,2)=ψ(Ω_(ω+1))
                        1 4 6 9 13=(0)(1,1,1)(2,1)(3,2)(4,3)=ψ(Ω_(ω+2))
                        1 4 6 10=(0)(1,1,1)(2,1)(3,2,1)=ψ(Ω_(ω2))
                        1 4 6 10 13 18=(0)(1,1,1)(2,1)(3,2,1)(3,2)(4,3,1)=ψ(Ω_(ω3))
                        1 4 7=(0)(1,1,1)(2,1,1)=ψ(Ω_(ω^2))
                        1 4 7 7=(0)(1,1,1)(2,1,1)=ψ(Ω_(ω^3))
                        1 4 7 9=(0)(1,1,1)(2,1,1)(3,1)=ψ(Ω_Ω)
                        1 4 7 9 4 7 9=(0)(1,1,1)(2,1,1)(3,1)(1,1,1)(2,1,1)(3,1)=ψ(Ω_Ω_Ω)
                        1 4 7 9 5=(0)(1,1,1)(2,1,1)(3,1)(2)=ψ(I)


                        IP属地:天津来自Android客户端14楼2024-03-23 17:19
                        收起回复
                          0-Y会了就试试展开1-Y
                          1,2,4=1,2,3,4,......(不整通项了太累了)
                          1,2,4,4=1,2,4,3,5,4,6,......
                          1,2,4,6=1,2,4,5,7,8,10,......
                          1,2,4,7=1,2,4,6,8,10,......
                          1,2,4,8=1,2,4,7,11,16,......
                          1,2,4,8,10=1,2,4,8,9,10,12,16,17,18,20,24,......
                          1,2,4,8,11=1,2,4,8,10,14,16,20,......
                          1,2,4,8,12=1,2,4,8,11,16,20,26,31,38,......
                          1,2,4,8,13=1,2,4,8,12,16,20,24,......
                          1,2,4,8,14=1,2,4,8,13,19,27,36,46,58......
                          1,2,4,8,15=1,2,4,8,14,22,32,44,58......
                          1,2,4,8,16=1,2,4,8,15,26,42,64,93......
                          1,3=1,2,2^2,2^3,2^4,2^5......


                          IP属地:天津来自Android客户端15楼2024-03-24 00:10
                          收起回复
                            1,3,3展开


                            IP属地:天津来自Android客户端16楼2024-03-24 09:32
                            收起回复
                              接下来就分析BMS顺便分析0-Y吧
                              1 4 7 9 6=(0)(1,1,1)(2,1,1)(3,1)(2,1)=ψ(I+ψ_I(I)*Ω)
                              1 4 7 9 6 4 7 9 5=(0)(1,1,1)(2,1,1)(3,1)(2,1)(1,1,1)(2,1,1)(3,1)(2)=ψ(I+ψ_I(I)^2)
                              1 4 7 9 6 5=(0)(1,1,1)(2,1,1)(3,1)(2,1)(2)=ψ(I+ψ_I(I)^2*ω)
                              1 4 7 9 6 6=(0)(1,1,1)(2,1,1)(3,1)(2,1)(2,1)=ψ(I+ψ_I(I)^2*Ω)
                              1 4 7 9 6 7=(0)(1,1,1)(2,1,1)(3,1)(2,1)(3)=ψ(I+ψ_I(I)^ω)
                              1 4 7 9 6 9=(0)(1,1,1)(2,1,1)(3,1)(2,1)(3,2)=ψ(I+ψ_I(I+1))
                              1 4 7 9 6 10=(0)(1,1,1)(2,1,1)(3,1)(2,1)(3,2,1)=ψ(I+ψ_I(I+ω))
                              1 4 7 9 6 10 15 17 7 =(0)(1,1,1)(2,1,1)(3,1)(2,1)(3,2,1)(4,2,1)(5,1)(3)=ψ(I+ψ_I(I+ψ_I(I)))?
                              1 4 7 9 6 10 15 17 10=(0)(1,1,1)(2,1,1)(3,1)(2,1)(3,2,1)(4,2,1)(5,1)(4)=ψ(I2)
                              1 4 7 9 7=(0)(1,1,1)(2,1,1)(3,1)(2,1,1)=ψ(Iω)


                              IP属地:天津来自Android客户端17楼2024-03-24 16:44
                              回复